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201204204011257 is a prime number
BaseRepresentation
bin101101101111111010000001…
…000110110111111011111001
3222101101221012220221001211111
4231233322001012313323321
5202333012202211330012
61551531534004400321
760244344512446246
oct5557720106677371
9871357186831744
10201204204011257
1159123250866307
121a6968809a60a1
1388366238282c5
14379849a60a5cd
15183dbb2d9cba7
hexb6fe811b7ef9

201204204011257 has 2 divisors, whose sum is σ = 201204204011258. Its totient is φ = 201204204011256.

The previous prime is 201204204011249. The next prime is 201204204011413. The reversal of 201204204011257 is 752110402402102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 158414041477696 + 42790162533561 = 12586264^2 + 6541419^2 .

It is a cyclic number.

It is not a de Polignac number, because 201204204011257 - 23 = 201204204011249 is a prime.

It is a super-3 number, since 3×2012042040112573 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (201204204011207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100602102005628 + 100602102005629.

It is an arithmetic number, because the mean of its divisors is an integer number (100602102005629).

Almost surely, 2201204204011257 is an apocalyptic number.

It is an amenable number.

201204204011257 is a deficient number, since it is larger than the sum of its proper divisors (1).

201204204011257 is an equidigital number, since it uses as much as digits as its factorization.

201204204011257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8960, while the sum is 31.

Adding to 201204204011257 its reverse (752110402402102), we get a palindrome (953314606413359).

The spelling of 201204204011257 in words is "two hundred one trillion, two hundred four billion, two hundred four million, eleven thousand, two hundred fifty-seven".