Base | Representation |
---|---|
bin | 10010101111010001… |
… | …010100111011000011 |
3 | 1220221020010110002202 |
4 | 102233101110323003 |
5 | 312201312033011 |
6 | 13124310303415 |
7 | 1311413532443 |
oct | 225721247303 |
9 | 56836113082 |
10 | 20120424131 |
11 | 85955004a5 |
12 | 3a96357b6b |
13 | 1b8861c912 |
14 | d8c2b2123 |
15 | 7cb60723b |
hex | 4af454ec3 |
20120424131 has 2 divisors, whose sum is σ = 20120424132. Its totient is φ = 20120424130.
The previous prime is 20120424113. The next prime is 20120424161. The reversal of 20120424131 is 13142402102.
Together with previous prime (20120424113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20120424131 - 26 = 20120424067 is a prime.
It is a super-2 number, since 2×201204241312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20120424101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060212065 + 10060212066.
It is an arithmetic number, because the mean of its divisors is an integer number (10060212066).
Almost surely, 220120424131 is an apocalyptic number.
20120424131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20120424131 is an equidigital number, since it uses as much as digits as its factorization.
20120424131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 20120424131 its reverse (13142402102), we get a palindrome (33262826233).
The spelling of 20120424131 in words is "twenty billion, one hundred twenty million, four hundred twenty-four thousand, one hundred thirty-one".
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