Base | Representation |
---|---|
bin | 11101010001111010100… |
… | …000010111100100001011 |
3 | 21010100120201010112112122 |
4 | 131101322200113210023 |
5 | 230431240100000021 |
6 | 4140202422001455 |
7 | 265240466544023 |
oct | 35217240274413 |
9 | 7110521115478 |
10 | 2012100000011 |
11 | 706365aa39a2 |
12 | 285b6027628b |
13 | 11798133c6aa |
14 | 6d55989ca83 |
15 | 37515402bab |
hex | 1d47a81790b |
2012100000011 has 2 divisors, whose sum is σ = 2012100000012. Its totient is φ = 2012100000010.
The previous prime is 2012099999999. The next prime is 2012100000089. The reversal of 2012100000011 is 1100000012102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2012100000011 is a prime.
It is not a weakly prime, because it can be changed into another prime (2012100008011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006050000005 + 1006050000006.
It is an arithmetic number, because the mean of its divisors is an integer number (1006050000006).
Almost surely, 22012100000011 is an apocalyptic number.
2012100000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012100000011 is an equidigital number, since it uses as much as digits as its factorization.
2012100000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 8.
Adding to 2012100000011 its reverse (1100000012102), we get a palindrome (3112100012113).
The spelling of 2012100000011 in words is "two trillion, twelve billion, one hundred million, eleven", and thus it is an aban number.
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