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20121001403 is a prime number
BaseRepresentation
bin10010101111010011…
…100001110110111011
31220221021012202222012
4102233103201312323
5312201434021103
613124330520135
71311421455446
oct225723416673
956837182865
1020121001403
118595865188
123a9659604b
131b887925b9
14d8c3c265d
157cb6bd2d8
hex4af4e1dbb

20121001403 has 2 divisors, whose sum is σ = 20121001404. Its totient is φ = 20121001402.

The previous prime is 20121001399. The next prime is 20121001409. The reversal of 20121001403 is 30410012102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20121001403 - 22 = 20121001399 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (20121001409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060500701 + 10060500702.

It is an arithmetic number, because the mean of its divisors is an integer number (10060500702).

Almost surely, 220121001403 is an apocalyptic number.

20121001403 is a deficient number, since it is larger than the sum of its proper divisors (1).

20121001403 is an equidigital number, since it uses as much as digits as its factorization.

20121001403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 20121001403 its reverse (30410012102), we get a palindrome (50531013505).

The spelling of 20121001403 in words is "twenty billion, one hundred twenty-one million, one thousand, four hundred three".