Base | Representation |
---|---|
bin | 1001001001100110011110… |
… | …00001111010110010001110 |
3 | 2122020120002001212010100011 |
4 | 10210303033001322302032 |
5 | 10114131003122413402 |
6 | 110443301131423434 |
7 | 4144462422525445 |
oct | 444631701726216 |
9 | 78216061763304 |
10 | 20121100201102 |
11 | 645834656456a |
12 | 230b72b8b4b7a |
13 | b2c5473bc474 |
14 | 4d7c1b755d5c |
15 | 24d5e1711ed7 |
hex | 124ccf07ac8e |
20121100201102 has 4 divisors (see below), whose sum is σ = 30181650301656. Its totient is φ = 10060550100550.
The previous prime is 20121100201073. The next prime is 20121100201123. The reversal of 20121100201102 is 20110200112102.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5030275050274 + ... + 5030275050277.
It is an arithmetic number, because the mean of its divisors is an integer number (7545412575414).
Almost surely, 220121100201102 is an apocalyptic number.
20121100201102 is a deficient number, since it is larger than the sum of its proper divisors (10060550100554).
20121100201102 is a wasteful number, since it uses less digits than its factorization.
20121100201102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10060550100553.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 20121100201102 its reverse (20110200112102), we get a palindrome (40231300313204).
The spelling of 20121100201102 in words is "twenty trillion, one hundred twenty-one billion, one hundred million, two hundred one thousand, one hundred two".
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