Base | Representation |
---|---|
bin | 11101010001111011001… |
… | …010010101000111101001 |
3 | 21010100121110211101202011 |
4 | 131101323022111013221 |
5 | 230431300404000131 |
6 | 4140203453435521 |
7 | 265240662210052 |
oct | 35217312250751 |
9 | 7110543741664 |
10 | 2012111000041 |
11 | 70637122742a |
12 | 285b63a9bba1 |
13 | 1179836c149c |
14 | 6d55b123729 |
15 | 375163770b1 |
hex | 1d47b2951e9 |
2012111000041 has 2 divisors, whose sum is σ = 2012111000042. Its totient is φ = 2012111000040.
The previous prime is 2012110999991. The next prime is 2012111000089. The reversal of 2012111000041 is 1400001112102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2011730906025 + 380094016 = 1418355^2 + 19496^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012111000041 - 211 = 2012110997993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2012110999985 and 2012111000030.
It is not a weakly prime, because it can be changed into another prime (2012111000941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006055500020 + 1006055500021.
It is an arithmetic number, because the mean of its divisors is an integer number (1006055500021).
Almost surely, 22012111000041 is an apocalyptic number.
It is an amenable number.
2012111000041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012111000041 is an equidigital number, since it uses as much as digits as its factorization.
2012111000041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2012111000041 its reverse (1400001112102), we get a palindrome (3412112112143).
The spelling of 2012111000041 in words is "two trillion, twelve billion, one hundred eleven million, forty-one", and thus it is an aban number.
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