Base | Representation |
---|---|
bin | 1001001001100110100000… |
… | …10101000111101101110101 |
3 | 2122020120010120220020021222 |
4 | 10210303100111013231311 |
5 | 10114131024213341041 |
6 | 110443303231120125 |
7 | 4144463106106232 |
oct | 444632025075565 |
9 | 78216116806258 |
10 | 20121122012021 |
11 | 6458357901418 |
12 | 230b737073045 |
13 | b2c54ba87c34 |
14 | 4d7c205d2789 |
15 | 24d5e35be74b |
hex | 124cd0547b75 |
20121122012021 has 64 divisors (see below), whose sum is σ = 22329233625600. Its totient is φ = 18072794234880.
The previous prime is 20121122011999. The next prime is 20121122012029. The reversal of 20121122012021 is 12021022112102.
It is a de Polignac number, because none of the positive numbers 2k-20121122012021 is a prime.
It is a super-3 number, since 3×201211220120213 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20121122012029) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1052295341 + ... + 1052314461.
It is an arithmetic number, because the mean of its divisors is an integer number (348894275400).
Almost surely, 220121122012021 is an apocalyptic number.
It is an amenable number.
20121122012021 is a deficient number, since it is larger than the sum of its proper divisors (2208111613579).
20121122012021 is a wasteful number, since it uses less digits than its factorization.
20121122012021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19566.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 20121122012021 its reverse (12021022112102), we get a palindrome (32142144124123).
The spelling of 20121122012021 in words is "twenty trillion, one hundred twenty-one billion, one hundred twenty-two million, twelve thousand, twenty-one".
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