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201213132120 = 23325711133715091
BaseRepresentation
bin1011101101100100111…
…1001011110101011000
3201020100220000011220200
42323121033023311120
511244041030211440
6232234103422200
720352151255230
oct2733117136530
9636326004820
10201213132120
1178374627330
1232bb5a54960
1315c88760a30
149a4b26ccc0
155379c05c30
hex2ed93cbd58

201213132120 has 768 divisors, whose sum is σ = 901810990080. Its totient is φ = 37548748800.

The previous prime is 201213132091. The next prime is 201213132163. The reversal of 201213132120 is 21231312102.

201213132120 is a `hidden beast` number, since 20 + 121 + 313 + 212 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 201213132093 and 201213132102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 13325775 + ... + 13340865.

It is an arithmetic number, because the mean of its divisors is an integer number (1174233060).

Almost surely, 2201213132120 is an apocalyptic number.

201213132120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201213132120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (450905495040).

201213132120 is an abundant number, since it is smaller than the sum of its proper divisors (700597857960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201213132120 is a wasteful number, since it uses less digits than its factorization.

201213132120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15176 (or 15169 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 201213132120 its reverse (21231312102), we get a palindrome (222444444222).

It can be divided in two parts, 201213 and 132120, that added together give a palindrome (333333).

The spelling of 201213132120 in words is "two hundred one billion, two hundred thirteen million, one hundred thirty-two thousand, one hundred twenty".