Base | Representation |
---|---|
bin | 10010101111010100… |
… | …110100100010010011 |
3 | 1220221021211222111201 |
4 | 102233110310202103 |
5 | 312202030340201 |
6 | 13124342052031 |
7 | 1311424365661 |
oct | 225724644223 |
9 | 56837758451 |
10 | 20121340051 |
11 | 8595a7665a |
12 | 3a9671a017 |
13 | 1b88880797 |
14 | d8c46dc31 |
15 | 7cb738801 |
hex | 4af534893 |
20121340051 has 2 divisors, whose sum is σ = 20121340052. Its totient is φ = 20121340050.
The previous prime is 20121340027. The next prime is 20121340069. The reversal of 20121340051 is 15004312102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20121340051 - 27 = 20121339923 is a prime.
It is not a weakly prime, because it can be changed into another prime (20121340021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060670025 + 10060670026.
It is an arithmetic number, because the mean of its divisors is an integer number (10060670026).
Almost surely, 220121340051 is an apocalyptic number.
20121340051 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121340051 is an equidigital number, since it uses as much as digits as its factorization.
20121340051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 20121340051 its reverse (15004312102), we get a palindrome (35125652153).
The spelling of 20121340051 in words is "twenty billion, one hundred twenty-one million, three hundred forty thousand, fifty-one".
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