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201220022011 = 1711836471883
BaseRepresentation
bin1011101101100110100…
…1011101111011111011
3201020101100222020001211
42323121221131323323
511244044311201021
6232234511223551
720352263652331
oct2733151357373
9636340866054
10201220022011
1178378502858
1232bb8217bb7
1315c8a003aa8
149a4c143b51
15537a6173e1
hex2ed9a5defb

201220022011 has 4 divisors (see below), whose sum is σ = 213056493912. Its totient is φ = 189383550112.

The previous prime is 201220022009. The next prime is 201220022057. The reversal of 201220022011 is 110220022102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201220022011 - 21 = 201220022009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201220021982 and 201220022000.

It is not an unprimeable number, because it can be changed into a prime (201220022711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5918235925 + ... + 5918235958.

It is an arithmetic number, because the mean of its divisors is an integer number (53264123478).

Almost surely, 2201220022011 is an apocalyptic number.

201220022011 is a deficient number, since it is larger than the sum of its proper divisors (11836471901).

201220022011 is a wasteful number, since it uses less digits than its factorization.

201220022011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11836471900.

The product of its (nonzero) digits is 32, while the sum is 13.

Adding to 201220022011 its reverse (110220022102), we get a palindrome (311440044113).

Subtracting from 201220022011 its reverse (110220022102), we obtain a palindrome (90999999909).

The spelling of 201220022011 in words is "two hundred one billion, two hundred twenty million, twenty-two thousand, eleven".

Divisors: 1 17 11836471883 201220022011