Base | Representation |
---|---|
bin | 10010101111010111… |
… | …011000010111111011 |
3 | 1220221100010002001112 |
4 | 102233113120113323 |
5 | 312202213324011 |
6 | 13124404310535 |
7 | 1311433162325 |
oct | 225727302773 |
9 | 56840102045 |
10 | 20122011131 |
11 | 8596394872 |
12 | 3a969a244b |
13 | 1b88a57081 |
14 | d8c5a6615 |
15 | 7cb81c58b |
hex | 4af5d85fb |
20122011131 has 4 divisors (see below), whose sum is σ = 20124909600. Its totient is φ = 20119112664.
The previous prime is 20122011109. The next prime is 20122011149. The reversal of 20122011131 is 13111022102.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13111022102 = 2 ⋅6555511051.
It is a cyclic number.
It is not a de Polignac number, because 20122011131 - 26 = 20122011067 is a prime.
It is a super-2 number, since 2×201220111312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20122011331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1438796 + ... + 1452713.
It is an arithmetic number, because the mean of its divisors is an integer number (5031227400).
Almost surely, 220122011131 is an apocalyptic number.
20122011131 is a deficient number, since it is larger than the sum of its proper divisors (2898469).
20122011131 is an equidigital number, since it uses as much as digits as its factorization.
20122011131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2898468.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 20122011131 its reverse (13111022102), we get a palindrome (33233033233).
The spelling of 20122011131 in words is "twenty billion, one hundred twenty-two million, eleven thousand, one hundred thirty-one".
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