Base | Representation |
---|---|
bin | 11101010010000001001… |
… | …000001110000010100011 |
3 | 21010100212110012111212022 |
4 | 131102001020032002203 |
5 | 230432002021010201 |
6 | 4140221431252055 |
7 | 265243316141012 |
oct | 35220110160243 |
9 | 7110773174768 |
10 | 2012211110051 |
11 | 70641279357a |
12 | 285b9151a02b |
13 | 11799b37308c |
14 | 6d56a542a79 |
15 | 3752004e41b |
hex | 1d48120e0a3 |
2012211110051 has 2 divisors, whose sum is σ = 2012211110052. Its totient is φ = 2012211110050.
The previous prime is 2012211110023. The next prime is 2012211110069. The reversal of 2012211110051 is 1500111122102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2012211110051 is a prime.
It is not a weakly prime, because it can be changed into another prime (2012211110251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006105555025 + 1006105555026.
It is an arithmetic number, because the mean of its divisors is an integer number (1006105555026).
Almost surely, 22012211110051 is an apocalyptic number.
2012211110051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012211110051 is an equidigital number, since it uses as much as digits as its factorization.
2012211110051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 2012211110051 its reverse (1500111122102), we get a palindrome (3512322232153).
The spelling of 2012211110051 in words is "two trillion, twelve billion, two hundred eleven million, one hundred ten thousand, fifty-one".
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