Base | Representation |
---|---|
bin | 101101110000001010100110… |
… | …100011011000100111000011 |
3 | 222101110122012000000021121022 |
4 | 231300022212203120213003 |
5 | 202333310140100030144 |
6 | 1551544041034020055 |
7 | 60245545021011254 |
oct | 5560124643304703 |
9 | 871418160007538 |
10 | 201222012111299 |
11 | 5912a859a98463 |
12 | 1a69a21087762b |
13 | 88382010793ca |
14 | 37992a9762b2b |
15 | 183e3a649bcee |
hex | b702a68d89c3 |
201222012111299 has 2 divisors, whose sum is σ = 201222012111300. Its totient is φ = 201222012111298.
The previous prime is 201222012111221. The next prime is 201222012111319. The reversal of 201222012111299 is 992111210222102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201222012111299 is a prime.
It is a super-2 number, since 2×2012220121112992 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201222012111209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100611006055649 + 100611006055650.
It is an arithmetic number, because the mean of its divisors is an integer number (100611006055650).
Almost surely, 2201222012111299 is an apocalyptic number.
201222012111299 is a deficient number, since it is larger than the sum of its proper divisors (1).
201222012111299 is an equidigital number, since it uses as much as digits as its factorization.
201222012111299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 35.
The spelling of 201222012111299 in words is "two hundred one trillion, two hundred twenty-two billion, twelve million, one hundred eleven thousand, two hundred ninety-nine".
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