Base | Representation |
---|---|
bin | 1001001001101000111010… |
… | …01010011000000110110011 |
3 | 2122020200110102102200220112 |
4 | 10210310131022120012303 |
5 | 10114141144211304303 |
6 | 110444035155331535 |
7 | 4144540050504632 |
oct | 444643512300663 |
9 | 78220412380815 |
10 | 20122411041203 |
11 | 6458959496099 |
12 | 230ba368b0bab |
13 | b2c6c5b514b3 |
14 | 4d7d03899519 |
15 | 24d66b8440d8 |
hex | 124d1d2981b3 |
20122411041203 has 2 divisors, whose sum is σ = 20122411041204. Its totient is φ = 20122411041202.
The previous prime is 20122411041191. The next prime is 20122411041319. The reversal of 20122411041203 is 30214011422102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20122411041203 - 212 = 20122411037107 is a prime.
It is a super-2 number, since 2×201224110412032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20122411046203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061205520601 + 10061205520602.
It is an arithmetic number, because the mean of its divisors is an integer number (10061205520602).
Almost surely, 220122411041203 is an apocalyptic number.
20122411041203 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122411041203 is an equidigital number, since it uses as much as digits as its factorization.
20122411041203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 20122411041203 its reverse (30214011422102), we get a palindrome (50336422463305).
The spelling of 20122411041203 in words is "twenty trillion, one hundred twenty-two billion, four hundred eleven million, forty-one thousand, two hundred three".
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