Base | Representation |
---|---|
bin | 1001001001101000111010… |
… | …01010011000100101100011 |
3 | 2122020200110102102210121102 |
4 | 10210310131022120211203 |
5 | 10114141144211340141 |
6 | 110444035155345015 |
7 | 4144540050513443 |
oct | 444643512304543 |
9 | 78220412383542 |
10 | 20122411043171 |
11 | 6458959497618 |
12 | 230ba368b216b |
13 | b2c6c5b52368 |
14 | 4d7d0389a123 |
15 | 24d66b84499b |
hex | 124d1d298963 |
20122411043171 has 2 divisors, whose sum is σ = 20122411043172. Its totient is φ = 20122411043170.
The previous prime is 20122411043153. The next prime is 20122411043179. The reversal of 20122411043171 is 17134011422102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20122411043171 is a prime.
It is a super-2 number, since 2×201224110431712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20122411043179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061205521585 + 10061205521586.
It is an arithmetic number, because the mean of its divisors is an integer number (10061205521586).
Almost surely, 220122411043171 is an apocalyptic number.
20122411043171 is a deficient number, since it is larger than the sum of its proper divisors (1).
20122411043171 is an equidigital number, since it uses as much as digits as its factorization.
20122411043171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 29.
Adding to 20122411043171 its reverse (17134011422102), we get a palindrome (37256422465273).
The spelling of 20122411043171 in words is "twenty trillion, one hundred twenty-two billion, four hundred eleven million, forty-three thousand, one hundred seventy-one".
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