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20123032002113 is a prime number
BaseRepresentation
bin1001001001101010000100…
…01011001001111001000001
32122020202001200212210010202
410210311002023021321001
510114143432143031423
6110444220540534545
74144561330544405
oct444650213117101
978222050783122
1020123032002113
116459147a60227
12230bb8a851455
13b2c7946a89a1
144d7d6213b105
1524d6a6102728
hex124d422c9e41

20123032002113 has 2 divisors, whose sum is σ = 20123032002114. Its totient is φ = 20123032002112.

The previous prime is 20123032002109. The next prime is 20123032002131. The reversal of 20123032002113 is 31120023032102.

Together with next prime (20123032002131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16895486809744 + 3227545192369 = 4110412^2 + 1796537^2 .

It is a cyclic number.

It is not a de Polignac number, because 20123032002113 - 22 = 20123032002109 is a prime.

It is not a weakly prime, because it can be changed into another prime (20123032002133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061516001056 + 10061516001057.

It is an arithmetic number, because the mean of its divisors is an integer number (10061516001057).

Almost surely, 220123032002113 is an apocalyptic number.

It is an amenable number.

20123032002113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20123032002113 is an equidigital number, since it uses as much as digits as its factorization.

20123032002113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 20123032002113 its reverse (31120023032102), we get a palindrome (51243055034215).

The spelling of 20123032002113 in words is "twenty trillion, one hundred twenty-three billion, thirty-two million, two thousand, one hundred thirteen".