Base | Representation |
---|---|
bin | 10010101111011011… |
… | …101100101111101011 |
3 | 1220221102020120220001 |
4 | 102233123230233223 |
5 | 312203011040042 |
6 | 13124444443431 |
7 | 1311445615552 |
oct | 225733545753 |
9 | 56842216801 |
10 | 20123143147 |
11 | 8596a98318 |
12 | 3a97249577 |
13 | 1b890623c3 |
14 | d8c7bcd99 |
15 | 7cb992bb7 |
hex | 4af6ecbeb |
20123143147 has 2 divisors, whose sum is σ = 20123143148. Its totient is φ = 20123143146.
The previous prime is 20123143133. The next prime is 20123143171. The reversal of 20123143147 is 74134132102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20123143147 - 227 = 19988925419 is a prime.
It is a super-2 number, since 2×201231431472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20123143177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10061571573 + 10061571574.
It is an arithmetic number, because the mean of its divisors is an integer number (10061571574).
Almost surely, 220123143147 is an apocalyptic number.
20123143147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20123143147 is an equidigital number, since it uses as much as digits as its factorization.
20123143147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 20123143147 its reverse (74134132102), we get a palindrome (94257275249).
The spelling of 20123143147 in words is "twenty billion, one hundred twenty-three million, one hundred forty-three thousand, one hundred forty-seven".
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