Base | Representation |
---|---|
bin | 11101010010001100100… |
… | …000111010000111001100 |
3 | 21010101100202122101220020 |
4 | 131102030200322013030 |
5 | 230432344421201104 |
6 | 4140252413422140 |
7 | 265251125611410 |
oct | 35221440720714 |
9 | 7111322571806 |
10 | 2012402131404 |
11 | 7065005a3765 |
12 | 28602549a950 |
13 | 1179cbb05672 |
14 | 6d587a68d40 |
15 | 37531bd32d9 |
hex | 1d48c83a1cc |
2012402131404 has 48 divisors (see below), whose sum is σ = 5366486404608. Its totient is φ = 574963388928.
The previous prime is 2012402131403. The next prime is 2012402131417. The reversal of 2012402131404 is 4041312042102.
It is a super-2 number, since 2×20124021314042 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2012402131403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7251004 + ... + 7523420.
It is an arithmetic number, because the mean of its divisors is an integer number (111801800096).
Almost surely, 22012402131404 is an apocalyptic number.
It is an amenable number.
2012402131404 is an abundant number, since it is smaller than the sum of its proper divisors (3354084273204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2012402131404 is a wasteful number, since it uses less digits than its factorization.
2012402131404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 360374 (or 360372 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 2012402131404 its reverse (4041312042102), we get a palindrome (6053714173506).
The spelling of 2012402131404 in words is "two trillion, twelve billion, four hundred two million, one hundred thirty-one thousand, four hundred four".
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