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2012410044353 is a prime number
BaseRepresentation
bin11101010010001100111…
…111000101111111000001
321010101101022112102102102
4131102030333011333001
5230432403432404403
64140253255200145
7265251253066262
oct35221477057701
97111338472372
102012410044353
11706505008895
12286028076055
13117a00646297
146d588b28969
1537532747b88
hex1d48cfc5fc1

2012410044353 has 2 divisors, whose sum is σ = 2012410044354. Its totient is φ = 2012410044352.

The previous prime is 2012410044331. The next prime is 2012410044473. The reversal of 2012410044353 is 3534400142102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1719591614224 + 292818430129 = 1311332^2 + 541127^2 .

It is a cyclic number.

It is not a de Polignac number, because 2012410044353 - 226 = 2012342935489 is a prime.

It is a super-2 number, since 2×20124100443532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2012410043353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006205022176 + 1006205022177.

It is an arithmetic number, because the mean of its divisors is an integer number (1006205022177).

Almost surely, 22012410044353 is an apocalyptic number.

It is an amenable number.

2012410044353 is a deficient number, since it is larger than the sum of its proper divisors (1).

2012410044353 is an equidigital number, since it uses as much as digits as its factorization.

2012410044353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 2012410044353 its reverse (3534400142102), we get a palindrome (5546810186455).

The spelling of 2012410044353 in words is "two trillion, twelve billion, four hundred ten million, forty-four thousand, three hundred fifty-three".