Base | Representation |
---|---|
bin | 11101010010001101000… |
… | …000100110111011100001 |
3 | 21010101101100021121010101 |
4 | 131102031000212323201 |
5 | 230432404033111231 |
6 | 4140253311502401 |
7 | 265251256342051 |
oct | 35221500467341 |
9 | 7111340247111 |
10 | 2012410441441 |
11 | 70650525a164 |
12 | 286028227a01 |
13 | 117a00754c4a |
14 | 6d588bcd561 |
15 | 375327c5661 |
hex | 1d48d026ee1 |
2012410441441 has 2 divisors, whose sum is σ = 2012410441442. Its totient is φ = 2012410441440.
The previous prime is 2012410441429. The next prime is 2012410441451. The reversal of 2012410441441 is 1441440142102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1977387190416 + 35023251025 = 1406196^2 + 187145^2 .
It is a cyclic number.
It is not a de Polignac number, because 2012410441441 - 225 = 2012376887009 is a prime.
It is not a weakly prime, because it can be changed into another prime (2012410441421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006205220720 + 1006205220721.
It is an arithmetic number, because the mean of its divisors is an integer number (1006205220721).
Almost surely, 22012410441441 is an apocalyptic number.
It is an amenable number.
2012410441441 is a deficient number, since it is larger than the sum of its proper divisors (1).
2012410441441 is an equidigital number, since it uses as much as digits as its factorization.
2012410441441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4096, while the sum is 28.
Adding to 2012410441441 its reverse (1441440142102), we get a palindrome (3453850583543).
The spelling of 2012410441441 in words is "two trillion, twelve billion, four hundred ten million, four hundred forty-one thousand, four hundred forty-one".
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