Base | Representation |
---|---|
bin | 1011101101101100001… |
… | …0010011011111011101 |
3 | 201020102222210101020121 |
4 | 2323123002103133131 |
5 | 11244121241410140 |
6 | 232241102314541 |
7 | 20352665624431 |
oct | 2733302233735 |
9 | 636388711217 |
10 | 201243310045 |
11 | 7838a669468 |
12 | 33003b88a51 |
13 | 15c91a989ab |
14 | 9a512869c1 |
15 | 537c6b764a |
hex | 2edb0937dd |
201243310045 has 4 divisors (see below), whose sum is σ = 241491972060. Its totient is φ = 160994648032.
The previous prime is 201243310027. The next prime is 201243310067. The reversal of 201243310045 is 540013342102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 150713215524 + 50530094521 = 388218^2 + 224789^2 .
It is a cyclic number.
It is not a de Polignac number, because 201243310045 - 211 = 201243307997 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20124331000 + ... + 20124331009.
It is an arithmetic number, because the mean of its divisors is an integer number (60372993015).
Almost surely, 2201243310045 is an apocalyptic number.
It is an amenable number.
201243310045 is a deficient number, since it is larger than the sum of its proper divisors (40248662015).
201243310045 is an equidigital number, since it uses as much as digits as its factorization.
201243310045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40248662014.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 201243310045 its reverse (540013342102), we get a palindrome (741256652147).
The spelling of 201243310045 in words is "two hundred one billion, two hundred forty-three million, three hundred ten thousand, forty-five".
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