20130003311081 has 2 divisors, whose sum is σ = 20130003311082. Its totient is φ = 20130003311080.

The previous prime is 20130003310981. The next prime is 20130003311147. The reversal of 20130003311081 is 18011330003102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20077523832025 + 52479479056 = 4480795^2 + 229084^2 .

It is a cyclic number.

It is not a de Polignac number, because 20130003311081 - 2¹⁸ = 20130003048937 is a prime.

It is a super-3 number, since 3×20130003311081³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (20130003311281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065001655540 + 10065001655541.

It is an arithmetic number, because the mean of its divisors is an integer number (10065001655541).

Almost surely, 2^{20130003311081} is an apocalyptic number.

It is an amenable number.

20130003311081 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130003311081 is an equidigital number, since it uses as much as digits as its factorization.

20130003311081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 20130003311081 its reverse (18011330003102), we get a palindrome (38141333314183).

The spelling of 20130003311081 in words is "twenty trillion, one hundred thirty billion, three million, three hundred eleven thousand, eighty-one".