Search a number
-
+
20130003311133 = 36710001103711
BaseRepresentation
bin1001001001110111000011…
…01100100101101000011101
32122021102001112121222022010
410210323201230211220131
510114302221321424013
6110451332412141433
74145226150646452
oct444734154455035
978242045558263
1020130003311133
1164610a5098941
1223113b5467879
13b30335a77701
144d8423d49829
1524d9631507c3
hex124ee1b25a1d

20130003311133 has 4 divisors (see below), whose sum is σ = 26840004414848. Its totient is φ = 13420002207420.

The previous prime is 20130003311081. The next prime is 20130003311147. The reversal of 20130003311133 is 33111330003102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20130003311133 - 28 = 20130003310877 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20130003311183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355000551853 + ... + 3355000551858.

It is an arithmetic number, because the mean of its divisors is an integer number (6710001103712).

Almost surely, 220130003311133 is an apocalyptic number.

It is an amenable number.

20130003311133 is a deficient number, since it is larger than the sum of its proper divisors (6710001103715).

20130003311133 is an equidigital number, since it uses as much as digits as its factorization.

20130003311133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6710001103714.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 20130003311133 its reverse (33111330003102), we get a palindrome (53241333314235).

The spelling of 20130003311133 in words is "twenty trillion, one hundred thirty billion, three million, three hundred eleven thousand, one hundred thirty-three".

Divisors: 1 3 6710001103711 20130003311133