Base | Representation |
---|---|
bin | 10010101111110101… |
… | …111001100010100111 |
3 | 1220221220011112020012 |
4 | 102233311321202213 |
5 | 312211240330203 |
6 | 13125252000435 |
7 | 1311561162413 |
oct | 225765714247 |
9 | 56856145205 |
10 | 20130011303 |
11 | 859a959486 |
12 | 3a9960011b |
13 | 1b8a5c85bc |
14 | d8d689d43 |
15 | 7cc39cbd8 |
hex | 4afd798a7 |
20130011303 has 4 divisors (see below), whose sum is σ = 20265112200. Its totient is φ = 19994910408.
The previous prime is 20130011281. The next prime is 20130011383. The reversal of 20130011303 is 30311003102.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30311003102 = 2 ⋅15155501551.
It is a cyclic number.
It is not a de Polignac number, because 20130011303 - 224 = 20113234087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20130011383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67550225 + ... + 67550522.
It is an arithmetic number, because the mean of its divisors is an integer number (5066278050).
Almost surely, 220130011303 is an apocalyptic number.
20130011303 is a deficient number, since it is larger than the sum of its proper divisors (135100897).
20130011303 is a wasteful number, since it uses less digits than its factorization.
20130011303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 135100896.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 20130011303 its reverse (30311003102), we get a palindrome (50441014405).
The spelling of 20130011303 in words is "twenty billion, one hundred thirty million, eleven thousand, three hundred three".
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