Base | Representation |
---|---|
bin | 11101010010110000001… |
… | …101111010100100001111 |
3 | 21010102220111202210122201 |
4 | 131102300031322210033 |
5 | 230440111242213203 |
6 | 4140432052222331 |
7 | 265302021206620 |
oct | 35226015724417 |
9 | 7112814683581 |
10 | 2013001132303 |
11 | 706788729a27 |
12 | 28617200a9a7 |
13 | 117a95c41575 |
14 | 6d603431a47 |
15 | 375695a4e1d |
hex | 1d4b037a90f |
2013001132303 has 32 divisors (see below), whose sum is σ = 2457508838400. Its totient is φ = 1611318272256.
The previous prime is 2013001132279. The next prime is 2013001132309. The reversal of 2013001132303 is 3032311003102.
It is a de Polignac number, because none of the positive numbers 2k-2013001132303 is a prime.
It is a super-2 number, since 2×20130011323032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013001132309) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15922243 + ... + 16048171.
It is an arithmetic number, because the mean of its divisors is an integer number (76797151200).
Almost surely, 22013001132303 is an apocalyptic number.
2013001132303 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2013001132303 is a deficient number, since it is larger than the sum of its proper divisors (444507706097).
2013001132303 is a wasteful number, since it uses less digits than its factorization.
2013001132303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 128311.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 2013001132303 its reverse (3032311003102), we get a palindrome (5045312135405).
The spelling of 2013001132303 in words is "two trillion, thirteen billion, one million, one hundred thirty-two thousand, three hundred three".
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