Base | Representation |
---|---|
bin | 101101110001010011011011… |
… | …101000101101011100000011 |
3 | 222101202010000220002212112111 |
4 | 231301103123220231130003 |
5 | 202341100313300023412 |
6 | 1552044012451240151 |
7 | 60254313625025014 |
oct | 5561233350553403 |
9 | 871663026085474 |
10 | 201300212111107 |
11 | 5915aa3893a77a |
12 | 1a6b13b58a9057 |
13 | 88426b42c1045 |
14 | 379cda742500b |
15 | 18414319122a7 |
hex | b714dba2d703 |
201300212111107 has 2 divisors, whose sum is σ = 201300212111108. Its totient is φ = 201300212111106.
The previous prime is 201300212111023. The next prime is 201300212111143. The reversal of 201300212111107 is 701111212003102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201300212111107 - 219 = 201300211586819 is a prime.
It is not a weakly prime, because it can be changed into another prime (201300212111197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100650106055553 + 100650106055554.
It is an arithmetic number, because the mean of its divisors is an integer number (100650106055554).
Almost surely, 2201300212111107 is an apocalyptic number.
201300212111107 is a deficient number, since it is larger than the sum of its proper divisors (1).
201300212111107 is an equidigital number, since it uses as much as digits as its factorization.
201300212111107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 22.
Adding to 201300212111107 its reverse (701111212003102), we get a palindrome (902411424114209).
The spelling of 201300212111107 in words is "two hundred one trillion, three hundred billion, two hundred twelve million, one hundred eleven thousand, one hundred seven".
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