Base | Representation |
---|---|
bin | 10010101111110101… |
… | …111100000001001011 |
3 | 1220221220012001011001 |
4 | 102233311330001023 |
5 | 312211241141301 |
6 | 13125252115431 |
7 | 1311561234121 |
oct | 225765740113 |
9 | 56856161131 |
10 | 20130021451 |
11 | 859a966071 |
12 | 3a99605b77 |
13 | 1b8a6000c7 |
14 | d8d68d911 |
15 | 7cc3a0c01 |
hex | 4afd7c04b |
20130021451 has 2 divisors, whose sum is σ = 20130021452. Its totient is φ = 20130021450.
The previous prime is 20130021413. The next prime is 20130021491. The reversal of 20130021451 is 15412003102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20130021451 is a prime.
It is not a weakly prime, because it can be changed into another prime (20130021491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065010725 + 10065010726.
It is an arithmetic number, because the mean of its divisors is an integer number (10065010726).
Almost surely, 220130021451 is an apocalyptic number.
20130021451 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130021451 is an equidigital number, since it uses as much as digits as its factorization.
20130021451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 20130021451 its reverse (15412003102), we get a palindrome (35542024553).
The spelling of 20130021451 in words is "twenty billion, one hundred thirty million, twenty-one thousand, four hundred fifty-one".
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