Base | Representation |
---|---|
bin | 11101010010110000010… |
… | …101001111100011000011 |
3 | 21010102220122101101200221 |
4 | 131102300111033203003 |
5 | 230440112240201001 |
6 | 4140432201323511 |
7 | 265302043430221 |
oct | 35226025174303 |
9 | 7112818341627 |
10 | 2013003053251 |
11 | 706789821193 |
12 | 286172796597 |
13 | 117a96464a18 |
14 | 6d6037b1b11 |
15 | 375698341a1 |
hex | 1d4b054f8c3 |
2013003053251 has 4 divisors (see below), whose sum is σ = 2028369488904. Its totient is φ = 1997636617600.
The previous prime is 2013003053239. The next prime is 2013003053311. The reversal of 2013003053251 is 1523503003102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2013003053251 - 217 = 2013002922179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013003053051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7683217630 + ... + 7683217891.
It is an arithmetic number, because the mean of its divisors is an integer number (507092372226).
Almost surely, 22013003053251 is an apocalyptic number.
2013003053251 is a deficient number, since it is larger than the sum of its proper divisors (15366435653).
2013003053251 is a wasteful number, since it uses less digits than its factorization.
2013003053251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15366435652.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 2013003053251 its reverse (1523503003102), we get a palindrome (3536506056353).
The spelling of 2013003053251 in words is "two trillion, thirteen billion, three million, fifty-three thousand, two hundred fifty-one".
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