Base | Representation |
---|---|
bin | 11101010010110000110… |
… | …011101000110011101000 |
3 | 21010102221012101012102221 |
4 | 131102300303220303220 |
5 | 230440121310133112 |
6 | 4140433044203424 |
7 | 265302201234004 |
oct | 35226063506350 |
9 | 7112835335387 |
10 | 2013011021032 |
11 | 706793273530 |
12 | 286175399574 |
13 | 117a97cc459b |
14 | 6d604887704 |
15 | 3756a3a9e07 |
hex | 1d4b0ce8ce8 |
2013011021032 has 32 divisors (see below), whose sum is σ = 4138423708320. Its totient is φ = 910360306240.
The previous prime is 2013011021029. The next prime is 2013011021033. The reversal of 2013011021032 is 2301201103102.
It is a junction number, because it is equal to n+sod(n) for n = 2013011020997 and 2013011021015.
It is not an unprimeable number, because it can be changed into a prime (2013011021033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 58041358 + ... + 58076029.
It is an arithmetic number, because the mean of its divisors is an integer number (129325740885).
Almost surely, 22013011021032 is an apocalyptic number.
2013011021032 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
2013011021032 is an abundant number, since it is smaller than the sum of its proper divisors (2125412687288).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2013011021032 is a wasteful number, since it uses less digits than its factorization.
2013011021032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116117601 (or 116117597 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 2013011021032 its reverse (2301201103102), we get a palindrome (4314212124134).
The spelling of 2013011021032 in words is "two trillion, thirteen billion, eleven million, twenty-one thousand, thirty-two".
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