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201301110431 = 1991011563369
BaseRepresentation
bin1011101101111001111…
…0110010111010011111
3201020121000112221110122
42323132132302322133
511244231041013211
6232250525225155
720354300130611
oct2733636627237
9636530487418
10201301110431
117840a257783
123301b4021bb
1315ca0a556c5
149a58c10db1
1553827d36db
hex2ede7b2e9f

201301110431 has 4 divisors (see below), whose sum is σ = 202312674000. Its totient is φ = 200289546864.

The previous prime is 201301110391. The next prime is 201301110467. The reversal of 201301110431 is 134011103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201301110431 - 226 = 201234001567 is a prime.

It is a super-2 number, since 2×2013011104312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201301610431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505781486 + ... + 505781883.

It is an arithmetic number, because the mean of its divisors is an integer number (50578168500).

Almost surely, 2201301110431 is an apocalyptic number.

201301110431 is a deficient number, since it is larger than the sum of its proper divisors (1011563569).

201301110431 is a wasteful number, since it uses less digits than its factorization.

201301110431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1011563568.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 201301110431 its reverse (134011103102), we get a palindrome (335312213533).

The spelling of 201301110431 in words is "two hundred one billion, three hundred one million, one hundred ten thousand, four hundred thirty-one".

Divisors: 1 199 1011563369 201301110431