Base | Representation |
---|---|
bin | 10010101111110110… |
… | …010001111001110011 |
3 | 1220221220100121010001 |
4 | 102233312101321303 |
5 | 312211302023331 |
6 | 13125254050431 |
7 | 1311562056346 |
oct | 225766217163 |
9 | 56856317101 |
10 | 20130111091 |
11 | 859aa17452 |
12 | 3a99649a17 |
13 | 1b8a631b4c |
14 | d8d6b445d |
15 | 7cc3bc561 |
hex | 4afd91e73 |
20130111091 has 2 divisors, whose sum is σ = 20130111092. Its totient is φ = 20130111090.
The previous prime is 20130111017. The next prime is 20130111167. The reversal of 20130111091 is 19011103102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20130111091 - 27 = 20130110963 is a prime.
It is not a weakly prime, because it can be changed into another prime (20130115091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065055545 + 10065055546.
It is an arithmetic number, because the mean of its divisors is an integer number (10065055546).
Almost surely, 220130111091 is an apocalyptic number.
20130111091 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130111091 is an equidigital number, since it uses as much as digits as its factorization.
20130111091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 20130111091 its reverse (19011103102), we get a palindrome (39141214193).
It can be divided in two parts, 2013011 and 1091, that added together give a palindrome (2014102).
The spelling of 20130111091 in words is "twenty billion, one hundred thirty million, one hundred eleven thousand, ninety-one".
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