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2013011130101 = 8912322586887
BaseRepresentation
bin11101010010110000110…
…100000011011011110101
321010102221012120202001112
4131102300310003123311
5230440121322130401
64140433050404405
7265302202166666
oct35226064033365
97112835522045
102013011130101
11706793338474
12286175430705
13117a9803211a
146d6048b536d
153756a3cc3bb
hex1d4b0d036f5

2013011130101 has 4 divisors (see below), whose sum is σ = 2013033806112. Its totient is φ = 2012988454092.

The previous prime is 2013011130083. The next prime is 2013011130131. The reversal of 2013011130101 is 1010311103102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013011130101 - 218 = 2013010867957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013011130131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11204321 + ... + 11382566.

It is an arithmetic number, because the mean of its divisors is an integer number (503258451528).

Almost surely, 22013011130101 is an apocalyptic number.

It is an amenable number.

2013011130101 is a deficient number, since it is larger than the sum of its proper divisors (22676011).

2013011130101 is an equidigital number, since it uses as much as digits as its factorization.

2013011130101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22676010.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 2013011130101 its reverse (1010311103102), we get a palindrome (3023322233203).

The spelling of 2013011130101 in words is "two trillion, thirteen billion, eleven million, one hundred thirty thousand, one hundred one".

Divisors: 1 89123 22586887 2013011130101