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201301123230000 = 24325417891125017
BaseRepresentation
bin101101110001010100010001…
…111100010110100100110000
3222101202012101101112111200200
4231301110101330112210300
5202341104200021330000
61552044243115515200
760254345330303223
oct5561242174264460
9871665341474620
10201301123230000
11591603661768a2
121a6b160aa58b00
1388427cacab651
14379d0524375ba
1518414868d8500
hexb71511f16930

201301123230000 has 300 divisors, whose sum is σ = 704024084371608. Its totient is φ = 53676869760000.

The previous prime is 201301123229981. The next prime is 201301123230001. The reversal of 201301123230000 is 32321103102.

201301123230000 is a `hidden beast` number, since 2 + 0 + 130 + 1 + 1 + 232 + 300 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (300).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (201301123230001) by changing a digit.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 1610127492 + ... + 1610252508.

Almost surely, 2201301123230000 is an apocalyptic number.

201301123230000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201301123230000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (352012042185804).

201301123230000 is an abundant number, since it is smaller than the sum of its proper divisors (502722961141608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201301123230000 is a wasteful number, since it uses less digits than its factorization.

201301123230000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142942 (or 142918 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 201301123230000 its reverse (32321103102), we get a palindrome (201333444333102).

The spelling of 201301123230000 in words is "two hundred one trillion, three hundred one billion, one hundred twenty-three million, two hundred thirty thousand".