Base | Representation |
---|---|
bin | 10010101111110110… |
… | …010010011001101011 |
3 | 1220221220100200220121 |
4 | 102233312102121223 |
5 | 312211302110011 |
6 | 13125254104111 |
7 | 1311562065322 |
oct | 225766223153 |
9 | 56856320817 |
10 | 20130113131 |
11 | 859aa18a37 |
12 | 3a9964b037 |
13 | 1b8a632a5b |
14 | d8d6b50b9 |
15 | 7cc3bce71 |
hex | 4afd9266b |
20130113131 has 2 divisors, whose sum is σ = 20130113132. Its totient is φ = 20130113130.
The previous prime is 20130113119. The next prime is 20130113149. The reversal of 20130113131 is 13131103102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20130113131 is a prime.
It is a super-2 number, since 2×201301131312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20130113111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065056565 + 10065056566.
It is an arithmetic number, because the mean of its divisors is an integer number (10065056566).
Almost surely, 220130113131 is an apocalyptic number.
20130113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130113131 is an equidigital number, since it uses as much as digits as its factorization.
20130113131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 20130113131 its reverse (13131103102), we get a palindrome (33261216233).
The spelling of 20130113131 in words is "twenty billion, one hundred thirty million, one hundred thirteen thousand, one hundred thirty-one".
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