Base | Representation |
---|---|
bin | 11101010010110000110… |
… | …100110100100101100011 |
3 | 21010102221012221222020001 |
4 | 131102300310310211203 |
5 | 230440121400101202 |
6 | 4140433055000431 |
7 | 265302203665645 |
oct | 35226064644543 |
9 | 7112835858201 |
10 | 2013011331427 |
11 | 706793465758 |
12 | 286175509117 |
13 | 117a980a2955 |
14 | 6d604928895 |
15 | 3756a41bd87 |
hex | 1d4b0d34963 |
2013011331427 has 2 divisors, whose sum is σ = 2013011331428. Its totient is φ = 2013011331426.
The previous prime is 2013011331379. The next prime is 2013011331449. The reversal of 2013011331427 is 7241331103102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013011331427 - 215 = 2013011298659 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2013011331395 and 2013011331404.
It is not a weakly prime, because it can be changed into another prime (2013011331467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006505665713 + 1006505665714.
It is an arithmetic number, because the mean of its divisors is an integer number (1006505665714).
Almost surely, 22013011331427 is an apocalyptic number.
2013011331427 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013011331427 is an equidigital number, since it uses as much as digits as its factorization.
2013011331427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 2013011331427 its reverse (7241331103102), we get a palindrome (9254342434529).
The spelling of 2013011331427 in words is "two trillion, thirteen billion, eleven million, three hundred thirty-one thousand, four hundred twenty-seven".
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