201301142131 has 2 divisors, whose sum is σ = 201301142132. Its totient is φ = 201301142130.

The previous prime is 201301142123. The next prime is 201301142143. The reversal of 201301142131 is 131241103102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201301142131 - 2³ = 201301142123 is a prime.

It is a super-2 number, since 2×201301142131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201301142099 and 201301142108.

It is not a weakly prime, because it can be changed into another prime (201301142171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100650571065 + 100650571066.

It is an arithmetic number, because the mean of its divisors is an integer number (100650571066).

Almost surely, 2^201301142131 is an apocalyptic number.

201301142131 is a deficient number, since it is larger than the sum of its proper divisors (1).

201301142131 is an equidigital number, since it uses as much as digits as its factorization.

201301142131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 201301142131 its reverse (131241103102), we get a palindrome (332542245233).

The spelling of 201301142131 in words is "two hundred one billion, three hundred one million, one hundred forty-two thousand, one hundred thirty-one".