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20130120120000 = 2635411101150991
BaseRepresentation
bin1001001001110111010001…
…01010001011011011000000
32122021102100200102110221110
410210323220222023123000
510114302441222320000
6110451352143523320
74145232066550212
oct444735052133300
978242320373843
1020130120120000
1164611550200a0
1223114285b9540
13b30354024c97
144d84356745b2
1524d96d525850
hex124ee8a8b6c0

20130120120000 has 560 divisors, whose sum is σ = 73324667395584. Its totient is φ = 4831680000000.

The previous prime is 20130120119983. The next prime is 20130120120053. The reversal of 20130120120000 is 2102103102.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 133244505 + ... + 133395495.

Almost surely, 220130120120000 is an apocalyptic number.

20130120120000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20130120120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (36662333697792).

20130120120000 is an abundant number, since it is smaller than the sum of its proper divisors (53194547275584).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20130120120000 is a wasteful number, since it uses less digits than its factorization.

20130120120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151138 (or 151113 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 20130120120000 its reverse (2102103102), we get a palindrome (20132222223102).

The spelling of 20130120120000 in words is "twenty trillion, one hundred thirty billion, one hundred twenty million, one hundred twenty thousand".