Base | Representation |
---|---|
bin | 1001001001110111010010… |
… | …10111100111000100110011 |
3 | 2122021102101111211120001012 |
4 | 10210323221113213010303 |
5 | 10114303002244422442 |
6 | 110451353251101135 |
7 | 4145232303022415 |
oct | 444735127470463 |
9 | 78242344746035 |
10 | 20130132029747 |
11 | 6461160815063 |
12 | 23114305a17ab |
13 | b30356634b7c |
14 | 4d84370949b5 |
15 | 24d96e5c9582 |
hex | 124ee95e7133 |
20130132029747 has 2 divisors, whose sum is σ = 20130132029748. Its totient is φ = 20130132029746.
The previous prime is 20130132029737. The next prime is 20130132029753. The reversal of 20130132029747 is 74792023103102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20130132029747 - 210 = 20130132028723 is a prime.
It is not a weakly prime, because it can be changed into another prime (20130132029737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065066014873 + 10065066014874.
It is an arithmetic number, because the mean of its divisors is an integer number (10065066014874).
Almost surely, 220130132029747 is an apocalyptic number.
20130132029747 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130132029747 is an equidigital number, since it uses as much as digits as its factorization.
20130132029747 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 127008, while the sum is 41.
The spelling of 20130132029747 in words is "twenty trillion, one hundred thirty billion, one hundred thirty-two million, twenty-nine thousand, seven hundred forty-seven".
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