2013013414131 has 4 divisors (see below), whose sum is σ = 2684017885512. Its totient is φ = 1342008942752.

The previous prime is 2013013414099. The next prime is 2013013414171. The reversal of 2013013414131 is 1314143103102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013013414131 - 2⁵ = 2013013414099 is a prime.

It is a super-2 number, since 2×2013013414131² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2013013414171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335502235686 + ... + 335502235691.

It is an arithmetic number, because the mean of its divisors is an integer number (671004471378).

Almost surely, 2^{2013013414131} is an apocalyptic number.

2013013414131 is a deficient number, since it is larger than the sum of its proper divisors (671004471381).

2013013414131 is an equidigital number, since it uses as much as digits as its factorization.

2013013414131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 671004471380.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 2013013414131 its reverse (1314143103102), we get a palindrome (3327156517233).

The spelling of 2013013414131 in words is "two trillion, thirteen billion, thirteen million, four hundred fourteen thousand, one hundred thirty-one".