201301401331 has 2 divisors, whose sum is σ = 201301401332. Its totient is φ = 201301401330.

The previous prime is 201301401319. The next prime is 201301401361. The reversal of 201301401331 is 133104103102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201301401331 - 2²⁷ = 201167183603 is a prime.

It is a super-2 number, since 2×201301401331² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201301401299 and 201301401308.

It is not a weakly prime, because it can be changed into another prime (201301401361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100650700665 + 100650700666.

It is an arithmetic number, because the mean of its divisors is an integer number (100650700666).

Almost surely, 2^201301401331 is an apocalyptic number.

201301401331 is a deficient number, since it is larger than the sum of its proper divisors (1).

201301401331 is an equidigital number, since it uses as much as digits as its factorization.

201301401331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 201301401331 its reverse (133104103102), we get a palindrome (334405504433).

The spelling of 201301401331 in words is "two hundred one billion, three hundred one million, four hundred one thousand, three hundred thirty-one".