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2013020032211 is a prime number
BaseRepresentation
bin11101010010110001010…
…110000000110011010011
321010102221211100000110022
4131102301112000303103
5230440131112012321
64140434005254055
7265302340644446
oct35226126006323
97112854300408
102013020032211
11706798368791
1228617840432b
13117a99b2b046
146d605b5165d
153756b089dab
hex1d4b1580cd3

2013020032211 has 2 divisors, whose sum is σ = 2013020032212. Its totient is φ = 2013020032210.

The previous prime is 2013020032183. The next prime is 2013020032273. The reversal of 2013020032211 is 1122300203102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2013020032211 - 214 = 2013020015827 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2013020032211.

It is not a weakly prime, because it can be changed into another prime (2013020037211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006510016105 + 1006510016106.

It is an arithmetic number, because the mean of its divisors is an integer number (1006510016106).

Almost surely, 22013020032211 is an apocalyptic number.

2013020032211 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013020032211 is an equidigital number, since it uses as much as digits as its factorization.

2013020032211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2013020032211 its reverse (1122300203102), we get a palindrome (3135320235313).

The spelling of 2013020032211 in words is "two trillion, thirteen billion, twenty million, thirty-two thousand, two hundred eleven".