Base | Representation |
---|---|
bin | 11101010010110001010… |
… | …110101010100100000011 |
3 | 21010102221211122201002201 |
4 | 131102301112222210003 |
5 | 230440131133001032 |
6 | 4140434013054031 |
7 | 265302342256243 |
oct | 35226126524403 |
9 | 7112854581081 |
10 | 2013020203267 |
11 | 706798475257 |
12 | 286178487317 |
13 | 117a99b8ab68 |
14 | 6d605b97b23 |
15 | 3756b0c08e7 |
hex | 1d4b15aa903 |
2013020203267 has 2 divisors, whose sum is σ = 2013020203268. Its totient is φ = 2013020203266.
The previous prime is 2013020203253. The next prime is 2013020203339. The reversal of 2013020203267 is 7623020203102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013020203267 - 219 = 2013019678979 is a prime.
It is a super-2 number, since 2×20130202032672 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2013020203867) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006510101633 + 1006510101634.
It is an arithmetic number, because the mean of its divisors is an integer number (1006510101634).
Almost surely, 22013020203267 is an apocalyptic number.
2013020203267 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013020203267 is an equidigital number, since it uses as much as digits as its factorization.
2013020203267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 2013020203267 its reverse (7623020203102), we get a palindrome (9636040406369).
The spelling of 2013020203267 in words is "two trillion, thirteen billion, twenty million, two hundred three thousand, two hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •