Base | Representation |
---|---|
bin | 10010101111110110… |
… | …101000001000001011 |
3 | 1220221220112012222121 |
4 | 102233312220020023 |
5 | 312211312431443 |
6 | 13125300032111 |
7 | 1311562615633 |
oct | 225766501013 |
9 | 56856465877 |
10 | 20130202123 |
11 | 859aa79889 |
12 | 3a99692637 |
13 | 1b8a664405 |
14 | d8d6d96c3 |
15 | 7cc3d94ed |
hex | 4afda820b |
20130202123 has 2 divisors, whose sum is σ = 20130202124. Its totient is φ = 20130202122.
The previous prime is 20130202097. The next prime is 20130202133. The reversal of 20130202123 is 32120203102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20130202123 - 25 = 20130202091 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20130202097 and 20130202106.
It is not a weakly prime, because it can be changed into another prime (20130202133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065101061 + 10065101062.
It is an arithmetic number, because the mean of its divisors is an integer number (10065101062).
Almost surely, 220130202123 is an apocalyptic number.
20130202123 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130202123 is an equidigital number, since it uses as much as digits as its factorization.
20130202123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 20130202123 its reverse (32120203102), we get a palindrome (52250405225).
The spelling of 20130202123 in words is "twenty billion, one hundred thirty million, two hundred two thousand, one hundred twenty-three".
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