Base | Representation |
---|---|
bin | 1001001001110111011011… |
… | …00110011101110111010001 |
3 | 2122021102120110102220020211 |
4 | 10210323231212131313101 |
5 | 10114303123434024131 |
6 | 110451404305004121 |
7 | 4145234124365203 |
oct | 444735546356721 |
9 | 78242513386224 |
10 | 20130203033041 |
11 | 6461197900972 |
12 | 2311450323641 |
13 | b3036826525a |
14 | 4d8442698773 |
15 | 24d9759525b1 |
hex | 124eed99ddd1 |
20130203033041 has 2 divisors, whose sum is σ = 20130203033042. Its totient is φ = 20130203033040.
The previous prime is 20130203033033. The next prime is 20130203033081. The reversal of 20130203033041 is 14033030203102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18127966713025 + 2002236320016 = 4257695^2 + 1415004^2 .
It is a cyclic number.
It is not a de Polignac number, because 20130203033041 - 23 = 20130203033033 is a prime.
It is not a weakly prime, because it can be changed into another prime (20130203033081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065101516520 + 10065101516521.
It is an arithmetic number, because the mean of its divisors is an integer number (10065101516521).
Almost surely, 220130203033041 is an apocalyptic number.
It is an amenable number.
20130203033041 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130203033041 is an equidigital number, since it uses as much as digits as its factorization.
20130203033041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 20130203033041 its reverse (14033030203102), we get a palindrome (34163233236143).
The spelling of 20130203033041 in words is "twenty trillion, one hundred thirty billion, two hundred three million, thirty-three thousand, forty-one".
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