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201302040403 is a prime number
BaseRepresentation
bin1011101101111010001…
…0010101111101010011
3201020121002022012011001
42323132202111331103
511244231310243103
6232251001202431
720354311053112
oct2733642257523
9636532265131
10201302040403
117840a832452
123301b790417
1315ca0cbca99
149a58db3c79
15538291901d
hex2ede895f53

201302040403 has 2 divisors, whose sum is σ = 201302040404. Its totient is φ = 201302040402.

The previous prime is 201302040367. The next prime is 201302040461. The reversal of 201302040403 is 304040203102.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201302040403 is a prime.

It is a super-2 number, since 2×2013020404032 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201302040473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100651020201 + 100651020202.

It is an arithmetic number, because the mean of its divisors is an integer number (100651020202).

Almost surely, 2201302040403 is an apocalyptic number.

201302040403 is a deficient number, since it is larger than the sum of its proper divisors (1).

201302040403 is an equidigital number, since it uses as much as digits as its factorization.

201302040403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 201302040403 its reverse (304040203102), we get a palindrome (505342243505).

The spelling of 201302040403 in words is "two hundred one billion, three hundred two million, forty thousand, four hundred three".