Base | Representation |
---|---|
bin | 1011101101111010001… |
… | …0100111101011101011 |
3 | 201020121002102212201221 |
4 | 2323132202213223223 |
5 | 11244231320104003 |
6 | 232251002522511 |
7 | 20354311504555 |
oct | 2733642475353 |
9 | 636532385657 |
10 | 201302113003 |
11 | 7840a881a52 |
12 | 3301b806437 |
13 | 15ca1016b44 |
14 | 9a58dd24d5 |
15 | 53829307bd |
hex | 2ede8a7aeb |
201302113003 has 2 divisors, whose sum is σ = 201302113004. Its totient is φ = 201302113002.
The previous prime is 201302112967. The next prime is 201302113037. The reversal of 201302113003 is 300311203102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201302113003 - 233 = 192712178411 is a prime.
It is not a weakly prime, because it can be changed into another prime (201302113043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100651056501 + 100651056502.
It is an arithmetic number, because the mean of its divisors is an integer number (100651056502).
Almost surely, 2201302113003 is an apocalyptic number.
201302113003 is a deficient number, since it is larger than the sum of its proper divisors (1).
201302113003 is an equidigital number, since it uses as much as digits as its factorization.
201302113003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 201302113003 its reverse (300311203102), we get a palindrome (501613316105).
Subtracting 201302113003 from its reverse (300311203102), we obtain a palindrome (99009090099).
The spelling of 201302113003 in words is "two hundred one billion, three hundred two million, one hundred thirteen thousand, three".
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