Base | Representation |
---|---|
bin | 11101010010110001100… |
… | …010100110001010111111 |
3 | 21010102222001112121112221 |
4 | 131102301202212022333 |
5 | 230440132433043012 |
6 | 4140434204110211 |
7 | 265302410664103 |
oct | 35226142461277 |
9 | 7112861477487 |
10 | 2013023331007 |
11 | 70679a211167 |
12 | 286179535367 |
13 | 117a9a7146b0 |
14 | 6d60636d903 |
15 | 3756b4dc507 |
hex | 1d4b18a62bf |
2013023331007 has 4 divisors (see below), whose sum is σ = 2167871279560. Its totient is φ = 1858175382456.
The previous prime is 2013023330977. The next prime is 2013023331061. The reversal of 2013023331007 is 7001333203102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013023331007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013026331007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77423974257 + ... + 77423974282.
It is an arithmetic number, because the mean of its divisors is an integer number (541967819890).
Almost surely, 22013023331007 is an apocalyptic number.
2013023331007 is a deficient number, since it is larger than the sum of its proper divisors (154847948553).
2013023331007 is a wasteful number, since it uses less digits than its factorization.
2013023331007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 154847948552.
The product of its (nonzero) digits is 2268, while the sum is 25.
Adding to 2013023331007 its reverse (7001333203102), we get a palindrome (9014356534109).
The spelling of 2013023331007 in words is "two trillion, thirteen billion, twenty-three million, three hundred thirty-one thousand, seven".
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