201303041343242 has 4 divisors (see below), whose sum is σ = 301954562014866. Its totient is φ = 100651520671620.

The previous prime is 201303041343197. The next prime is 201303041343311. The reversal of 201303041343242 is 242343140303102.

201303041343242 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 188937698102521 + 12365343240721 = 13745461^2 + 3516439^2 .

It is a junction number, because it is equal to n+sod(n) for n = 201303041343199 and 201303041343208.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50325760335809 + ... + 50325760335812.

Almost surely, 2^{201303041343242} is an apocalyptic number.

201303041343242 is a deficient number, since it is larger than the sum of its proper divisors (100651520671624).

201303041343242 is a wasteful number, since it uses less digits than its factorization.

201303041343242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100651520671623.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 201303041343242 its reverse (242343140303102), we get a palindrome (443646181646344).

The spelling of 201303041343242 in words is "two hundred one trillion, three hundred three billion, forty-one million, three hundred forty-three thousand, two hundred forty-two".