Base | Representation |
---|---|
bin | 1001001001110111100111… |
… | …01000011100010001101010 |
3 | 2122021102211111211102121021 |
4 | 10210323303220130101222 |
5 | 10114303330334322442 |
6 | 110451422321403054 |
7 | 4145236463406604 |
oct | 444736350342152 |
9 | 78242744742537 |
10 | 20130304214122 |
11 | 6461239a297a3 |
12 | 231147a19948a |
13 | b3038320050b |
14 | 4d8451cb6174 |
15 | 24d97e78be67 |
hex | 124ef3a1c46a |
20130304214122 has 8 divisors (see below), whose sum is σ = 30196913904036. Its totient is φ = 10064666246112.
The previous prime is 20130304214093. The next prime is 20130304214123. The reversal of 20130304214122 is 22141240303102.
It can be written as a sum of positive squares in 2 ways, for example, as 19570263021241 + 560041192881 = 4423829^2 + 748359^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×201303042141223 (a number of 41 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (20130304214123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242878683 + ... + 242961550.
Almost surely, 220130304214122 is an apocalyptic number.
20130304214122 is a deficient number, since it is larger than the sum of its proper divisors (10066609689914).
20130304214122 is a wasteful number, since it uses less digits than its factorization.
20130304214122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 485860952.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 20130304214122 its reverse (22141240303102), we get a palindrome (42271544517224).
The spelling of 20130304214122 in words is "twenty trillion, one hundred thirty billion, three hundred four million, two hundred fourteen thousand, one hundred twenty-two".
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