Base | Representation |
---|---|
bin | 11101010010110010000… |
… | …111110111100010000001 |
3 | 21010102222201221000001212 |
4 | 131102302013313202001 |
5 | 230440142433221231 |
6 | 4140435153335505 |
7 | 265302560016245 |
oct | 35226207674201 |
9 | 7112881830055 |
10 | 2013033101441 |
11 | 7067a47848aa |
12 | 286180867595 |
13 | 117a9c75590b |
14 | 6d607794425 |
15 | 3756c2bc42b |
hex | 1d4b21f7881 |
2013033101441 has 2 divisors, whose sum is σ = 2013033101442. Its totient is φ = 2013033101440.
The previous prime is 2013033101389. The next prime is 2013033101449. The reversal of 2013033101441 is 1441013303102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1653847440400 + 359185661041 = 1286020^2 + 599321^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013033101441 - 222 = 2013028907137 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013033101449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006516550720 + 1006516550721.
It is an arithmetic number, because the mean of its divisors is an integer number (1006516550721).
Almost surely, 22013033101441 is an apocalyptic number.
It is an amenable number.
2013033101441 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013033101441 is an equidigital number, since it uses as much as digits as its factorization.
2013033101441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 2013033101441 its reverse (1441013303102), we get a palindrome (3454046404543).
The spelling of 2013033101441 in words is "two trillion, thirteen billion, thirty-three million, one hundred one thousand, four hundred forty-one".
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